What is the relationship between E and arcs BC and AD?

by

Crystal M. Wood

In my experiment I found that the exterior angle
equals the sum of the two nonadjacent interior angles. ACD=CAE+CEA

Let a = CEA, b=CAE, and c = ACD.

Because I know that a+b=c

a
= c-b

a =1/2arcAD-1/2arcBC