What is the relationship between E and arcs BC and AD?

by

Crystal M. Wood

 

In my experiment I found that the exterior angle equals the sum of the two nonadjacent interior angles. ACD=CAE+CEA

Let a = CEA, b=CAE, and c = ACD.

 

Because I know that a+b=c

                                 a = c-b

                                                           a =1/2arcAD-1/2arcBC