Freddy and Frieda
| The Frog Race
Two frogs have a race. One frog makes a jump of 80 cm
once every 5 seconds. The other frog makes a jump of 15 cm every 1 second.
The rules of the race state that the frogs must cross a line 5 meters away
and then return to the starting point. Which frog wins the race?
Two frogs are in a race. The frogs must
cross the finish line which is 5 meters away. They then have to return to
the starting point which means going 5 meters back. Freddy the Frog jumps 80
cm every 5 seconds on the clock. Frieda Frog jumps 15 cm every second on
the clock. Who wins?
Solve/Investigate the Problem
First, I began thinking about the
metric system in terms of meters, naturally, and a silver meter stick that I
own. I began remembering my conversions such as 100 cm = 1 meter, 1000 mm =
1 meter. Those are the two that came to mind.
of the Problem
In order to carry out this
problem, I have to multiply 100 times 10 to get 1000 cm for the total race length
in cm since they have to go 5 meters each way. I convert to cm since the
problem gives me the length each frog jumps in the cm unit. If Freddy jumps
80 cm every 5 seconds, which means that he takes 62.5 seconds to finish the
race. First, I divided 1000 by 80 which is 12.5. This tells me how many 5 second
“chunks” he took to jump. Then, I multiply 12.5 by 5 and get
62.5 seconds or 1 minute and 2.5 seconds. Now for Frieda. Frieda jumps 15
cm every second. I take 1000 and divide it by 15 which equals 66.66. This means
that Frieda uses 66.66 one second jumps for the race. So, I multiply 66.66
by 1 and get the same number, 66.66, of course. So in terms of minutes and
seconds, Frieda uses 1 minute and 6.66 seconds to finish the race. Freddy
wins! Poor Frieda…
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